270=-0.5x^2+36x-40

Solution for 270=-0.5x^2+36x-40 equation:

270=-0.5x^2+36x-40

We move all terms to the left:

270-(-0.5x^2+36x-40)=0

We get rid of parentheses

0.5x^2-36x+40+270=0

We add all the numbers together, and all the variables

0.5x^2-36x+310=0

a = 0.5; b = -36; c = +310;
Δ = b2-4ac
Δ = -362-4·0.5·310
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-26}{2*0.5}=\frac{10}{1}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+26}{2*0.5}=\frac{62}{1}
=62
$